Sainik School Class 6 Divisibility Rules
Mastering Sainik School Class 6 Divisibility Rules: A Guide for Sainik School Class 6 Students
Divisibility rules are simple shortcuts that help determine whether a number can be evenly divided by another without performing long division. For students at Sainik School, mastering these rules is crucial for excelling in mathematics, particularly when dealing with larger numbers. In this post, we study the Sainik School class 6 Divisibility Rules and related questions that students need to understand.
Let’s explore the key divisibility rules that students preparing for Sainik School Class 6 should know.
Divisibility by 2
A number is divisible by 2 if its last digit (unit’s place) is even. This means the digit must be 0, 2, 4, 6, or 8.
Examples:
- 246 is divisible by 2 because the last digit is 6.
- 375 is not divisible by 2 because the last digit is 5.
Divisibility by 3
A number is divisible by 3 if the sum of its digits is divisible by 3.
Examples:
- For 123, the sum of the digits is 1 + 2 + 3 = 6. Since 6 is divisible by 3, 123 is divisible by 3.
- For 236, the sum is 2 + 3 + 6 = 11. Since 11 is not divisible by 3, 236 is not divisible by 3.
Divisibility by 4
A number is divisible by 4 if the last two digits form a number divisible by 4.
Examples:
- For 312, the last two digits are 12. Since 12 is divisible by 4, 312 is divisible by 4.
- For 145, the last two digits are 45. Since 45 is not divisible by 4, 145 is not divisible by 4.
Divisibility by 5
A number is divisible by 5 if its last digit is either 0 or 5.
Examples:
- 340 is divisible by 5 because the last digit is 0.
- 273 is not divisible by 5 because the last digit is 3.
Divisibility by 6
A number is divisible by 6 if it is divisible by both 2 and 3.
Examples:
- 72 is divisible by 2 (last digit is 2) and by 3 (7 + 2 = 9, which is divisible by 3). Therefore, 72 is divisible by 6.
- 53 is not divisible by 2 (last digit is 3), so it cannot be divisible by 6.
Divisibility by 8
A number is divisible by 8 if the last three digits form a number divisible by 8.
Examples:
- For 2,456, the last three digits are 456. Since 456 is divisible by 8, 2,456 is divisible by 8.
- For 7,132, the last three digits are 132. Since 132 is not divisible by 8, 7,132 is not divisible by 8.
Divisibility by 9
A number is divisible by 9 if the sum of its digits is divisible by 9.
Examples:
- For 729, the sum of the digits is 7 + 2 + 9 = 18. Since 18 is divisible by 9, 729 is divisible by 9.
- For 821, the sum is 8 + 2 + 1 = 11. Since 11 is not divisible by 9, 821 is not divisible by 9.
Divisibility by 10
A number is divisible by 10 if its last digit is 0.
Examples:
- 230 is divisible by 10 because the last digit is 0.
- 349 is not divisible by 10 because the last digit is 9.
Divisibility by 11
A number is divisible by 11 if the difference between the sum of the digits in odd positions and the sum of the digits in even positions is either 0 or divisible by 11.
Examples:
- For 1,221: (1 + 2) – (2 + 1) = 3 – 3 = 0. Since the difference is 0, 1,221 is divisible by 11.
- For 3,528: (3 + 2) – (5 + 8) = 5 – 13 = -8. Since -8 is not divisible by 11, 3,528 is not divisible by 11.
Why Divisibility Rules Matter?
For Sainik School students, understanding and applying divisibility rules can make mathematical calculations faster and more efficient. These rules not only save time but also enhance problem-solving skills, which are essential for competitive exams and higher-level mathematics.
Conclusion
Divisibility rules are essential tools in a student’s mathematical toolkit. By mastering these rules, Class 6 students at Sainik Schools can develop a strong foundation in arithmetic, setting the stage for more complex mathematical concepts. Remember, practice is key—so keep practicing these rules until they become second nature!
Very Important Questions on Sainik School Class 6 Divisibility Rules
Ques 1: Which one of the following numbers is divisible by 9?
a) 2876423
b) 9866003
c) 2345678
d) 460602
Answer – d) 460602
Solution:
2+8+7+6+4+2+3=32
9+8+6+6+0+0+3=32
2+3+4+5+6+7+8=35
4+6+0+6+0+2=18
18 is completely divisible by 9 so the answer is 460602
Ques 2: 7386016 is completely divisible by which number?
a) 3
b) 4
c) 9
d) 5
Answer – b (4)
Solution:
7+3+8+6+0+1+6=31
31=3+1=4
4 is not completely divisible by 3 and 9
The last two digits in 7386016 is 16
16 is completely divisible by 4
so 7386016 is completely divisible by 4
Ques 3: Find the greatest number of four digits which is exactly divisible by 91.
a) 9819
b) 9919
c) 9991
d) 9199
Answer – b (9919)
Solution
The greatest 4 digit number = 9999
Required Number = 9999-80=9919
For more such questions on Sainik School class 6 Divisibility Rules, download Shaurya Bharat app now: https://play.google.com/store/apps/details?id=com.shauryabharat
How to crack the AISSEE 2025 and RMS CET 2024 examinations?
Entrance examinations for Rashtriya Military School and Sainik School will take place in December 2024 and January 2025 respectively for academic session 2025-26. The best idea to start preparation is to start early so that students get sufficient time to prepare and polish themselves. The Sainik School and RMS Entrance Exams are a tough nut to crack. The standards and competition are way higher than one could think. Getting admission into Sainik School and RMS is the dream of thousands of young children. However, only a few can turn this dream into reality.
To succeed in this competitive environment, candidates need to prepare thoroughly, maintain a disciplined study routine, and focus on developing a strong foundation in the relevant subjects. Regular practice, solving sample papers, and mock tests can help in building confidence and improving performance. Maintaining physical fitness and participating in extracurricular activities can enhance overall candidacy.
It is important to remember that the competition is tough. However, dedication, hard work, and a positive mindset can significantly increase your chances of securing admission to a Sainik School or RMS. Here, Shaurya Bharat can be a perfect guide to students. Shaurya Bharat is the best offline and online platform for students preparing for the Sainik School, RMS, and RIMC entrance examinations.
Offline Classes
We conduct offline coaching for Sainik School and RMS (School + Coaching) at our campus in Jodhpur, Rajasthan.
Click the following link for a virtual tour of Shaurya Bharat Sainik School and Defence Academy. https://www.youtube.com/watch?v=H1dDOpZ-kh8
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Online Classes
Online classes are conducted through the Shaurya Bharat app. The Shaurya Bharat app provides the best content in the form of live classes, video lectures, and e-books.
Also, it offers topic-wise practice tests and pattern-based live exams. The live exams are based exactly on the pattern of the main examination. This gives students a well-required practice and a look and feel of the main examination. It makes them well-equipped to handle and overcome the examination pressure with minimum ease.
Useful Links
To know more about the Shaurya Bharat app logon to https://shauryabharat.com/
For more information about the Sainik School and RMS entrance exams for class 6, log on to https://shauryabharat.com/elite-schools/aissee-sainik-school-class-6/ and https://shauryabharat.com/elite-schools/rashtriya-military-school-rms-class-6/
For more information about the Sainik School and RMS entrance exam for class 9, log on to https://shauryabharat.com/elite-schools/aissee-sainik-school-class-9/ and https://shauryabharat.com/elite-schools/rashtriya-military-school-rms-class-9/
To download the detailed notification, submit the online application and download the admit card log on to https://exams.nta.ac.in/AISSEE/and https://www.rashtriyamilitaryschools.edu.in/
Use the following link to download the Shaurya Bharat app – The best digital platform to prepare for the Sainik School: https://play.google.com/store/apps/details?id=com.shauryabharat
